The proportion of hydraulic pumps and motor devices in the hydraulic system is very important. A good hydraulic system requires a good hydraulic pump and a good motor. Therefore, when configuring the hydraulic pump and the motor , We need our special attention. So, how to choose hydraulic pump and motor device? Motor power calculation After the specification and model of the hydraulic pump are selected according to the pressure and flow, the power of the motor driving the hydraulic pump can be calculated as follows: P = pQ/60.
In the formula, P is the motor power, the unit is KW; p is the maximum working pressure of the hydraulic pump, the unit is MPa; Q is the output flow of the hydraulic pump, the unit is L/min; the following hydraulic system manufacturers give you an example .
It is known that the displacement of the hydraulic pump is 136 ml/rev, the motor speed is 970 r/min, the maximum working pressure of the system is 12 MPa, and the power required by the system and the power of the selected motor are calculated. Solution: (1) The output flow of the pump is equal to the displacement multiplied by the speed, that is: Q = qn = 136 (ml/rev) × 970 r/min = 131920 (ml/min) = 131.92 (l/min) (2 ), the power required by the system, considering the efficiency of the pump, the motor power is generally 1.05 ~ 1.25 times the required power ND = (1.1 ~ 1.32.525) N = 28.5 ~ 32.4 (kW) Check the relevant motor manual, the selected motor When the power is 30kW, it is more suitable.
Calculation of hydraulic pump and motor power
Question 1. When calculating, do you calculate the rated flow and rated pressure of the hydraulic pump, or the actual flow and actual pressure of the pump?
Answer: It should be calculated according to the actual flow and pressure used, otherwise the motor selected may be very large and cause waste of resources.
Question 2. There is a formula for calculating the pump power: flow Qx pressure p/612, can this formula also be used?
Answer: This formula can also be used. The difference between the calculated result and the above formula is very small, but in this formula, the unit of pressure is kgf/cm2, not MPa.
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